4x^2+4x-168=04

Solution for 4x^2+4x-168=04 equation:

4x^2+4x-168=04

We move all terms to the left:

4x^2+4x-168-(04)=0

We add all the numbers together, and all the variables

4x^2+4x-172=0

a = 4; b = 4; c = -172;
Δ = b2-4ac
Δ = 42-4·4·(-172)
Δ = 2768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2768}=\sqrt{16*173}=\sqrt{16}*\sqrt{173}=4\sqrt{173}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{173}}{2*4}=\frac{-4-4\sqrt{173}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{173}}{2*4}=\frac{-4+4\sqrt{173}}{8}
$